Statement : If two half reaction with electrode potential `E_(1)^(@)` and `E_(2)^(@)` gives a third reaction then, `DeltaG_(3)^(@) = DeltaG_(1)^(@) + DeltaG_(2)^(@)` Explanation : `E_(3)^(@) = E_(1)^(@) + E_(2)^(@)`

Statement : If two half reaction with electrode potential `E_(1)^(@)`

1.	Statement : If two half reaction with electrode potential `E_(1)^(@)` and `E_(2)^(@)` gives a third reaction then, `DeltaG_(3)^(@) = DeltaG_(1)^(@) + DeltaG_(2)^(@)` Explanation : `E_(3)^(@) = E_(1)^(@) + E_(2)^(@)`
Answer» Correct Answer - A In such case `E^(@)` are not additive.

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Define molar conductivity of a solution and explain how molar conductivity changes with change in concentration of a solution for a weak and a strong electrolyte.
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Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

Statement : If two half reaction with electrode potential `E_(1)^(@)` and `E_(2)^(@)` gives a third reaction then, `DeltaG_(3)^(@) = DeltaG_(1)^(@) + DeltaG_(2)^(@)` Explanation : `E_(3)^(@) = E_(1)^(@) + E_(2)^(@)`

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