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Steel rod at 40^(@)C is observed to be 1 m long when measured by a brass scale which is correct at 0^(@)C. correct length of the steel rod at 0^(@)C is (alpha_("steel")=12xx10^(-6)//1^(@)Candalpha_("Brass")=19xx10^(-6)//1^(@)C) |
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Answer» 99.89 cm |
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