Stomach acid, a dilute solution of HCl can be neutralised by reaction with aluminig hydroxide Al (OH)_(3) + 3HCl (aq) to AlCl _(3) + 3H _(2)O How many milliliters of 0.1 M Al (OH) _(3) solution are needed to neutralise 21 mL of 0.1 M HCl ?

Stomach acid, a dilute solution of HCl can be neutralised by reaction

1.	Stomach acid, a dilute solution of HCl can be neutralised by reaction with aluminig hydroxide Al (OH)_(3) + 3HCl (aq) to AlCl _(3) + 3H _(2)O How many milliliters of 0.1 M Al (OH) _(3) solution are needed to neutralise 21 mL of 0.1 M HCl ?
Answer» 1) 14 mL 2) 7 mL 3) 21 mL 4) none of these Solution :`M _(1) XX V _(1) = M_(2) xx V _(2)` `because 0.1 M AL (OH) _(3)` GIVES `3 xx 0.1 =0.3 M OH ^(-)` ions `0.3 xx V _(1) = 0.1 xx 21` `V _(1) = (0.1 xx 21)/( 0.3) = 7 ml`