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Stomach acid, a dilute solution of HCl can be neutralised by reaction with Aluminium hydroxideAl(OH)_(3) + 3HCl(aq)to + AICI_(3) + 3H_(2)O How many millilitres of 0.1 M Al(OH)_(3) solution are needed to neutralise 21 mL of 0.1 M HCI? |
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Answer» 14 mL `:’0.1M AL(OH)_(3) gives 3 XX 0.1 = 0.3 M OH^(-) ions` `0.3 xx V_(1) = 0.1xx 21` `V_(1)=(0.1xx21)/(0.3)=7ml`
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