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stone thrown upward X3 second to attain maximum height calculate first initial velocity of stone second maximum height attained by stone third net displacement when it come back |
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Answer» stone is thrown from down to up then at some time after REACHING its MAXIMUM height, its velocity will come back to 0.According to 1s equation of motion,➣ Since ball is thrown against GRAVITY that's why G = - 10 m/s²0 = u + ( - 10)(3) 0 = u - 30 m/s➣ When ball comes back to us then its initial position is same as before.➣ Since displacement is all about final position - initial position so answer will be 0 because here final and initial position are same. |
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