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Stopping potential depends on planks constant (h), current (I), universal gravitational constant (G) and speed of light (C) choose the correct option for the dimension of stopping potential (V)(1) hI–1G1C5 (2) h–1I1G–1C6 (3) h0I1G1C6 (4) h0I-1G–1C5 |
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Answer» Answer is (4) V = K (h)a (I)b (G)c (C)d (V is voltage) we know [h] = ML2T–1 [I] = A [G] = M–1 L3 T–2 [C] = L T–1 [V] = M L2 T–3 A–1 M L2 T–3 A–1 = (M L2 T–1)a (A)b (M–1L3T-2)c (LT–1)d ML2T–3A–1 = Ma–c L2a+3c+d T–a–2c–d Ab a – c = 1………………(1) 2a + 3c + d = 2………………(2) –a –2c –d = –3 ………………(3) b = –1………………(4) on solving c = –1 a = 0 d = 5, b = –1 V = K (h)° (I)–1 (G)–1 (C) 5 |
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