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Structure of a mixed oxide is cubic close-packed (c.c.p.) The cubic cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B . The formula of the oxide is : |
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Answer» `A_2B_3O_4` `therefore` No. of octahedral voids=n No. of TETRAHEDRAL voids=2n Divalent metal ions A present =`"2n"/4=n/2` Monovalent Metal ions B present =n `therefore` Ratio `A:B:O^(2-)=n/2:n:n=1/2:1:1` HENCE, formula =`AB_2O_2` |
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