1.

Structure of a mixed oxide is cubic close-packed (c.c.p.) The cubic cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B . The formula of the oxide is :

Answer»

`A_2B_3O_4`
`AB_2O_2`
`ABO_2`
`A_2BO_2`

Solution :SUPPOSE NUMBER of `O^(2-)` ions in close PACKING =n
`therefore` No. of octahedral voids=n
No. of TETRAHEDRAL voids=2n
Divalent metal ions A present =`"2n"/4=n/2`
Monovalent Metal ions B present =n
`therefore` Ratio `A:B:O^(2-)=n/2:n:n=1/2:1:1`
HENCE, formula =`AB_2O_2`


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