InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Structure of a mixed oxide is cubic close-packed (c.c.p) the cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. the formula of the oxide is :A. `A_(2)B_(3)O_(4)`B. `AB_(2)O_(2)`C. `ABO_(2)`D. `A_(2)BO_(2)` |
|
Answer» Correct Answer - A Suppose number of ` O^(2-)` ions in close packing = n No. of octahedral voids = n No. of tetradral voids = 2n Divalent metal ions A present = `(2n)/4 = n/2 ` Monovalent metal ions B present =n Ratio `A :B : O^(2-) = n/2 : n :n = 1/2 :1:1 ` Hence, formula = ` AB_(2)O_(2)` |
|