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InterviewSolution
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Structure of a mixed oxide is cubic closed - packed (ccp) .The cubic unit cell of mixed oxide is composed of oxide ions .One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovelent metal B .The formula of the oxide isA. `ABO_2`B. `A_2BO_2`C. `A_2B_3O_4`D. `AB_2O_2` |
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Answer» Correct Answer - D For ccp arrangement , number of `O^(2-)` ions = 4 Number of octahedral voids =4 Thus number of tetrahedral voids = 8 As `A^(2+)` (divalent matal) occupy 1/4 tetrahedral voids , Thus , number of `A^(2+)` ions `=1/4xx8=2` Again, `B^+` occupied all octahedral voids hence, number of B ions = 4 `therefore " Structure of oxide " = AB_2O_2` |
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