InterviewSolution
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InterviewSolution
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STT e SELOD 105 1 951 (1)fie (onon) 4DIT Be MRJEpsk) B LB bayush धन्य Seah 0 |
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Answer» 2)135 and 225Since 225 > 135, we apply the division lemma to 225 and 135 to obtain225 = 135 × 1 + 90Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain135 = 90 × 1 + 45We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain90 = 2 × 45 + 0Since the remainder is zero, the process stops.Since the divisor at this stage is 45,Therefore, the HCF of 135 and 225 is 45. 1)We know that 504 > 156 so,504=156×3+46156=46×3+1846=18×2+1018=10×1+810=8×1+28=2×4+0Hence, now the remainder has become zero so pur procedure stops and thus we get the HCF = 2 |
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