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Study the given circuit and find out: (i) Current in `12 Omega` resistor, (ii) Difference in the reading of `A_(1) and A_(2)`, if any. |
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Answer» (i) Current through `12Omega` resistor. `I=(V)/(R)=(6)/(12)=(1)/(2)=0.5A` (ii) No difference since the ammeters are connected in series, there will be same reading in them. |
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