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Sub. Que. : Explain sigma-bond formation in ethene. |
Answer» Solution :Now one sp ORBITAL of carbon combine with sp orbital of other carbon and form sigma BOND. Remaining TWO `sp^(2)` orbital. Combine with is orbital of H and form four C-H sigma bond. In this way four C-H sigma bond and two carbon & four Hydrogen are in one plane  Now the each carbon has one non hybride 2p orbital which side by side OVERLAP and form `pi`-bond. in ethene both carbon has `sp^(2)` hybridization . So ethene is planar. 
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