Subtract 3a + 4b – 2c from 6a – 2b + 3c in row method.

1.	Subtract 3a + 4b – 2c from 6a – 2b + 3c in row method.
Answer» Let A = 6a – 2b + 3c, B = 3a + 4b – 2c Subtracting 3a + 4b – 2c from 6a – 2b + 3c is equal to adding additive inverse of 3a + 4b – 2c to 6a – 2b + 3c i.e., A – B = A + (-B) additive inverse of (3a + 4b – 2c) = – (3a + 4b – 2c) = – 3a – 4b + 2c A – B = A + (-B) = 6a – 2b + 3c + (- 3a – 4b + 2c) = 6a – 2b + 3c – 3a – 4b +2c = (6 – 3)a – (2 + 4)b + (3 + 2)c Thus, the required answer = 3a – 6b + 5c

Answer»

Let A = 6a – 2b + 3c, B = 3a + 4b – 2c

Subtracting 3a + 4b – 2c from 6a – 2b + 3c is equal to adding additive inverse of 3a + 4b – 2c to 6a – 2b + 3c

i.e., A – B = A + (-B)

additive inverse of (3a + 4b – 2c) = – (3a + 4b – 2c)

= – 3a – 4b + 2c A – B = A + (-B)

= 6a – 2b + 3c + (- 3a – 4b + 2c)

= 6a – 2b + 3c – 3a – 4b +2c

= (6 – 3)a – (2 + 4)b + (3 + 2)c

Thus, the required answer = 3a – 6b + 5c

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