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Subtract 5a2 – 7ab + 5b2 from 3ab – 2a2 – 2b2 and find the degree of the expression |
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Answer» We have (3ab – 2a2 – 2b2) – (5a2 – 7ab + 5b2) = 3ab – 2a2 – 2b2 – 5a2 + 7ab – 5b2 = (3ab + 7ab) + (- 2 – 5)a2 + (- 2 – 5)b2 = 10 ab + (-7)a2 + (-7)b2 = 10ab – 7a2 – 7b2 Degree of the expression is 2. |
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