

InterviewSolution
1. |
Subtract the second expression from the first expression(i) 2a + b, a – b(ii) x + 2y + z , – x – y – 3z(iii) 3a2 – 8ab – 2b2, 3a2 – 4ab+6b2(iv) 4pq – 6p2 – 2q2, 9p2(v) 7 – 2x – 3x2, 2x2 – 5 x – 3(vi) 5x2 – 3xy – 7y2 , 3x2 – xy – 2y2(vii) 6m3 + 4m2 + 7m – 3 , 3m3 + 4 |
Answer» (i) 2a + b, a – b = 2a + b – a + b = (2a – a) + (b + b) = a + 2b ii) (x + 2y + z) – ( – x – y – 3z) = x + + z + x + y + 3z =(x + x) + (2y + y) +(z + 3z) = 2x + 3y + 4z iii) (3a2 – 8ab – 2b2) – (3a2 – 4ab + 6b2) = 3a2 – 8ab – 2b2 – 3a2 +4ab – 6b2 = (3a2 – 3a2) + ( – 8ab + 4ab) + (2b2 – 6b2) = 0 – 4ab – 8b2 = – 4ab – 8b2 iv) (4pq – 6p2 – 2q2) – (9p2) = 4pq – 6p2 – 2q2 – 9p2 = 4pq – 15p2 – 2q2 v) (7 – 2x – 3x2) – (2x2 – 5x – 3) =7 – 2x – 3x2 – 2x2 + 5x + 3 = ( – 3x2 – 2x2) + ( – 2x + 5x) + (7 + 3) = – 5x2 + 3x + 10 vi) (5x2 – 3xy – 7y2) – (3x2 – xy – 2y2) = 5x2– 3xy – 7y2 – 3x2 + xy + 2y2 = (5x2 – 3x2) + ( – 3xy + xy) + ( – 7y2 + 2y2) = 2x2 – 2xy – 5y2 viii) (6m3 + 4m2 + 7m – 3) – (3m3 + 4) = 6m3 + 4m2 + 7m – 3 – 3m3 – 4 = (6m3 – 3m3) + 4m2 + 7m + (- 3 – 4) = 3m3 + 4m2 + 7m – 7 |
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