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Subtract the second polynomial from the first. i. 5x2 – 2y + 9 ; 3X2 + 5y – 7 ii. 2x2 + 3x + 5 ; x2 – 2x + 3 |
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Answer» i. (5x2– 2y + 9) – (3x2+ 5y – 7) = 5x2 – 2y+ 9 – 3x2 – 5y + 1 = 5x2 – 3x2 – 2y – 5y + 9 + 7 = 2x2 – 1y + 16 ii. (2x2 + 3x + 5) – (x2 – 2x + 3) = 2x2 + 3x + 5 – x2 + 2x – 3 = 2x2 – x2 + 3x + 2x + 5 – 3 = x2+ 5x + 2 |
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