Subtract the second polynomial from the first. i. x2 – 9x + √3; �

1.	Subtract the second polynomial from the first. i. x2 – 9x + √3; – 19x + √3 + 7x2 ii. 2ab2 + 3a2b – 4ab; 3ab – 8ab2 + 2a2b
Answer» i. x² – 9x + √3 -(- 19x + √3 + 7x²) = x² – 9x + √3 + 19x – √ 3 – 7x² = x² – 7x²– 9x + 19x + √3 – √3 = – 6x² + 10x ii. (2ab² + 3a²b – 4ab) – (3ab – 8ab² + 2a²b) = 2ab² + 3a²b – 4ab – 3ab + 8ab² – 2a²b = 2ab² + 8ab² + 3a²b – 2a²b – 4ab – 3ab = 10ab² + a²b – 7ab

Subtract the second polynomial from the first. i. x2 – 9x + √3; – 19x + √3 + 7x2 ii. 2ab2 + 3a2b – 4ab; 3ab – 8ab2 + 2a2b

Answer»

i. x² – 9x + √3 -(- 19x + √3 + 7x²)

= x² – 9x + √3 + 19x – √ 3 – 7x²

= x² – 7x²– 9x + 19x + √3 – √3

= – 6x² + 10x

ii. (2ab² + 3a²b – 4ab) – (3ab – 8ab² + 2a²b)

= 2ab² + 3a²b – 4ab – 3ab + 8ab² – 2a²b

= 2ab² + 8ab² + 3a²b – 2a²b – 4ab – 3ab

= 10ab² + a²b – 7ab