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Subtract: x3 + 2x2y + 6xy2 − y3 from y3−3xy2−4x2y |
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Answer» Given x3 + 2x2y + 6xy2 − y3 and y3−3xy2−4x2y = (y3 – 3xy2 – 4x2y) – (x3 + 2x2y + 6xy2 – y3) = y3 – 3xy2 – 4x2y – x3 – 2x2y – 6xy2 + y3 = y3 + y3– 3xy2– 6xy2– 4x2y – 2x2y – x3 = 2y3– 9xy2 – 6x2y – x3 |
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