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Sulphide ioninalkaline solutionreacts withsolidsulphur toform polysulphide ions havingformulae S_2^(2-), S_3^(2-), S_4^(2-) and so on. The equilibrium constant for the formationof S_2^(2-) is 12(K_1) andfor the formation of S_3^(2-) is 132(K_2) both from S and S^(2-). What is the equilibrium constant for the formation of S_3^(2-) from S_2^(2-) and S ? |
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Answer» Solution :`S+S^(2-) harr S_(2)^(2-), K_(1)=12` `2S+S^(2-) harr S_(3)^(2-), K_(2)=132` `S_(2)^(2-)+S harr S_(3)^(2-), K=(K_(2))/(K_(1))=(132)/(12)=11` |
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