InterviewSolution
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InterviewSolution
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Sulphide ions in alkaline solution react with solid sulphur to form polyvalent sulphide ions. The equilibrium constant for the formation of `S_(2)^(2-)` and `S_(3)^(2-)` from `S` and `S^(2-)` ions is `1.7` and `5.3` respectively. Calculate equilibrium constant for the formation of `S_(3)^(2-)` from `S_(2)^(2-)` and `S`.A. `1.33`B. `3.11`C. `4.21`D. `1.63` |
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Answer» `{:("Given",S_((s)),+,S^(2-),hArr,S_(2)^(2-),, ,K_(c_(1))=1.7),(,2S_((s)),+,S^(2-),hArr,S_(3)^(2-),, ,K_(c_(2))=5.3):}` `:. K_(c_(1))=([S_(2)^(2-)])/([S^(2-)])=1.7` ….(`1`) `K_(c_(2))=([S_(3)^(2-)])/([S^(2-)])=5.3` ….(`2`) Nor for `S_(2)^(2-)+S_((s))hArrS_(3)^(2-)` `K_(c)=([S_(3)^(2-)])/([S_(2)^(2-)])` `:.` By eqs. (`2`) and (`1`) , `(K_(c_(2)))/(K_(c_(1)))=([S_(3)^(2-)])/([S_(2)^(2-)])=K_(c)` `:. K_(c)=3.11` |
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