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Sulphur on reaction with concentrated `HNO_3`. Gives `(A)` which reacts with reacts with `NaOH` gives `(B).(A)` and `(B)` areA. `H_2 SO_3, Na_2 S_2 O_3`B. `NO_2, Na_2 S`C. `H_2 SO_4, Na_2 SO_4`D. `H_2 S_2 O_3, Na_2 S_2 O_3` |
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Answer» Correct Answer - C `S + HNO_(3) rarr (A)` `(A) + overset(conc.) (NaOH) rarr (B)` `S + 6 HNO_(3) rarr underset((A))(H_(2) SO_(4) + 6 NO_(2) + 2 H_(2) O` `underset((A)) (H_(2) SO_(4)) + 2 NaOH rarr Na_(2) SO_(4) + 2 H_(2) O`. |
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