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Sulphur reacts with `HNO_(3)` to formA. `H_(2)SO_(3)`B. `H_(2)SO_(4)`C. `SO_(2)`D. `SO_(3)` |
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Answer» Correct Answer - B `2HI+H_(2)SO_(4) to 6NO_(2)+H_(2)SO_(4)+2H_(2)O` `S+H_(2)O+3O to H_(2)SO_(4)` =`6HNO_(3)+S to 6NO_(2)+H_(2)SO_(4)+2H_(2)O` |
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