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Sulphuric acid oxidises hydroiodic acid to iodine and forms hydrogen sulphide and water. |
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Answer» Solution :a) The SKELETON equation is written as `H_(2)SO_(4)+HIrarrH_(2)S+I_(2)+H_(2)O` b) Focusing on the oxidation NUMBERS `overset(+1)(H_(2))overset(+6)(S)overset(-2)(O_(4))+overset(+1)(H)overset(-1)(I)rarroverset(+1)(H_(2))overset(-2)(S)+overset(0)(I_(2))` c) Locating atoms undergoing CHANGE in oxideation numbers `H_(2)overset(+6)(SO_(4))+Hoverset(-1)(I)rarrH_(2)overset(-2)(S)+overset(0)(I_(2))` d) Determining the change in oxidation numbers  e) Cris - crossing these changes in the oxidation numbers `H_(2)SO_(4)+8HIrarrH_(2)S+I_(2)` f) Balancing HTE atoms other than hydrogen and oxygen `H_(2)SO_(4)+8HIrarrH_(2)S+4I_(2)+H_(2)O` g) Blancing the atoms hydrogen and oxygen `H_(2)SO_(4)+8HIrarrH_(2)S+4I_(2)+4H_(2)O` This is the balanced EQUATIONS. |
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