Sulphurtrioxide is prepared by following two reaction : (i) Cu_(2)S + O_(2) rarr Cu_(2) O + SO_(2) (ii) 2SO_(2) + O_(2) rarr 2SO_(3) How many gramSO_(3) of are produced from 159 g of Cu_(2)S (Atomic mass of Cu = 63.5, S = 32, O = 16 g/mole)

Sulphurtrioxide is prepared by following two reaction : (i) Cu_(2)S +

1.	Sulphurtrioxide is prepared by following two reaction : (i) Cu_(2)S + O_(2) rarr Cu_(2) O + SO_(2) (ii) 2SO_(2) + O_(2) rarr 2SO_(3) How many gramSO_(3) of are produced from 159 g of Cu_(2)S (Atomic mass of Cu = 63.5, S = 32, O = 16 g/mole)
Answer» 64 G 160 g 128g 80 g Solution :(i) `Cu_(2)S + O_(2) rarr Cu_(2) O + SO_(2)` Mw.of `Cu_(2)S= 159` g/mole So, 159 g `Cu_(2)S` willproduce 1 mole of `SO_(2)(64 g SO_(2))` (ii) `2SO_(2) + O_(2) rarr 2SO_(3)` `128 g SO_(2)` will produce `160 g SO_(3)` `:.64 g SO_(2)` will produce `80 g SO_(3)`