1.

Sum of 3 numbean AP is 13 and

Answer»

Let the numbers be a-d,a,a+dHence sum is 18 that isa-d+a+a+d=3a=18a=6Now product is 162Hence(a-d)*a*(a+d)=162(6-d)*6*(6+d)=162(36-d^2)*6=16236-d^2=27d^2=9d=+-3If d=3the ap will be 3,6,9,..If d=-3then ap will be 3,0,-3,-6,..



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