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Sum of first ‘n’ natural numbers is ………………..A) \(\frac{n+3}{2}\)B) \(\frac{n}{2}\)C) \(\frac{n-1}{2}\)D) \(\frac{n(n+1)}{2}\) |
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Answer» Correct option is (D) \(\frac{n(n+1)}{2}\) Sum of first n natural numbers = 1+2+3+ .... +n = \(\frac{n(n+1)}{2}\) Correct option is D) \(\frac{n(n+1)}{2}\) |
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