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Sum of first n terms is 3n2 + n. Find the 22nd term. |
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Answer» a22 = S22 - S22-1 a22 = 3(22)²+22 - [3(21)²+21] a22 = 1474 - 1344 a22 = 130 Hence the 22nd term of the AP is 130. |
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