1.

Sum of first n terms is 3n2 + n. Find the 22nd term.

Answer»

a22 = S22 - S22-1

a22 = 3(22)²+22 - [3(21)²+21]

a22 = 1474 - 1344

a22 = 130

Hence the 22nd term of the AP is 130.



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