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Sum of last two terms of an A.P. is 60. If first termis 11 and common differences 2, then the numberof terms in the A.P. is(a) 2(c) 11(b) 20(d) 19 |
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Answer» a=11d=2Let number of terms be n+1an+an-1=60a+(n-1)d + a+(n+1-1)d=6011+(n-1)2 + 11+n(2)=6022+2n-2+2n=604n+20=604n=60-20=40n=40/4=10 Number of terms are 11Option c is correct |
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