1.

Sum of probabilities of getting an even number and an odd number when a die is rolled is A) 1/2B) 1/6C) 1/3D) 1

Answer»

Correct option is (D) 1

Possible outcomes when a die is rolled are S = {1, 2, 3, 4, 5, 6}.

\(\therefore\) Total outcomes is n(S) = 6

E = Event of getting an even number = {2, 4, 6}

0 = Event of getting an odd number = {1, 3, 5}

\(\therefore\) n(E) = 3 & n(0) = 3

\(\therefore\) P(E) \(=\frac{n(E)}{n(S)}=\frac36=\frac12\) and

P(0) \(=\frac{n(0)}{n(S)}=\frac36=\frac12\)

\(\because\) P(E) + P(0) \(=\frac12+\frac12\) = 1

Hence, the sum of probabilities of getting an even number and an odd number when a die is rolled is 1.

Correct option is   D) 1


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