Sum of the cubes of first n natural numbers – InterviewSolution

1.

Sum of the cubes of first n natural numbers

Answer»

Let

S = 1³ + 2³ + 3³ + 4³ + ..... + n³

Then, S = ∑n³ = \(\bigg\{\frac{n(n+1)}{2}\bigg\}^2\) = (∑n)²

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