1.

Sum of three consecutive numbers is 3003. Find the lowest number.1. 9982. 9993. 10004. 1001

Answer» Correct Answer - Option 3 : 1000

Calculations:

Let the numbers be (x – 1), x, (x + 1)

According to problem,

x – 1 + x +  x + 1 = 3003

⇒ 3x = 3003

⇒ x = 1001

Lowest number = x – 1 

⇒ 1001 – 1 = 1000

∴ Required lowest number is 1000



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