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`sum_(r=1)^(n) 1/(log_(2^(r))4)` is equal toA. `(n(n+1))/2`B. `(n(n+1)(2n+1))/12`C. `1/(n(n+1))`D. `(n(n+1))/4` |
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Answer» Correct Answer - D `sum_(r=1)^(n)1/(log_(2^(t))4)1/(1/rlog_(2)^(4))=r/2` `sum_(r=1)^(n) r/2=1/2(1+2+3+……+n)=(n(n+1))/4` |
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