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sunil take 5 days more than Anil to complete a certain work. 4 days after starting the work, Anil left the work. The remaining work was done by sunil in 5 days. Find how many days each will take to complete the work. |
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Answer» let anil can do in x daysunil can do in x+5 days1 day work of sunil + anil= 1/x + 1/x+5= x+5+x/x(x+5) parts4 days both work= 4(2x+5)/x^2+5xremaining work =1- 8x+20/x^2 + 5x= x^2+5x-8x-20/x^2+5x= x^2-3x-20/x^2+5xsunil 5 days alone work= 5/x+5A/S5/x+5 = x^2-3x-20/x(x+5)x^2-3x-20=5xx^2-8x-20=0x^2-10x +2x-20=0x(x-10)+2(x-10)=0(x-10)(x+2)=0either x-10=0, x=10or x+2=0, x= -2(neglected)so Anil can do work in 10 day alone sunil can do in 15 day |
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