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Suppose ∫1−7cos2xsin7xcos2xdx=g(x)sin7x+C, where C is arbitrary constant of integration. Then the value of g′(0)+g′′(π4) is |
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Answer» Suppose ∫1−7cos2xsin7xcos2xdx=g(x)sin7x+C, where C is arbitrary constant of integration. Then the value of g′(0)+g′′(π4) is |
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