Suppose 10^(-18)J of light energy is needed by the interior of the human eye to see an object. How many photon of green light (lambda = 550nm) are needed to generate this amount of energy ?

Suppose 10^(-18)J of light energy is needed by the interior of the hum

1.	Suppose 10^(-18)J of light energy is needed by the interior of the human eye to see an object. How many photon of green light (lambda = 550nm) are needed to generate this amount of energy ?
Answer» SOLUTION :`E_("PHOTON") = (hc)/(lambda) = (6.625xx10^(-34)xx3xx10^8)/(550xx10^(-9))` `=3.61xx10^(-19) J = `1 Photon `10^(-18) J = (10^(-18))/(3.61xx 10^(-19)) = (10)/(3.61) = 2.77 = 3`