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Suppose `a_(1),a_(2),a_(3)` are in A.P. and `b_(1),b_(2),b_(3)` are in H.P. and let `/_=|(a_(1)-b_(1),a_(1)-b_(2),a_(1)-b_(3)),(a_(2)-b_(1),a_(2)-b_(2),a_(2)-b_(3)),(a_(3)-b_(1),a_(3)-b_(2),a_(3)-b_(3))|` thenA. `/_ "is independent of "a_(1),a_(2),a_(3),b_(1),b_(2),b_(3)`B. `a_(1)-/_,a_(2)-2/_,a_(3)-3/_` are in H.P.C. `b_(1)+/_,b_(2)+/_^(2),b^(3)+/_` are in H.P.D. none of these |
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Answer» Correct Answer - A::B::C abc |
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