InterviewSolution
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InterviewSolution
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Suppose a,b,c are in A.P and `a^2,b^2,c^2` are in G.P If `a |
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Answer» `a,b,c` are in AP. Note whenever 3 terms are given in AP assume them to be m-d,m,m+d. `a+b+c=3m=3/2` `m=1/2` given `a^2,b^2,c^2` are in G.P. so `b^4=a^2 xx c^2` `m^4=(m-d)^2 xx (m+d)^2` on solving we get, `d^2(d^2-2m^2)=0` d cannot be equal to 0 so `(d^2-2m^2)=0` `m=1/2` thus `d= +-1/sqrt(2)` using +/- value will give the same AP but opposite order so it wont affect the terms. now `a=1/2-1/sqrt(2)` |
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