Suppose A->xBz and B->y, then the simplified grammar would be:(a) A->xyz(b) A->xBz|xyz(c) A->xBz|B|y(d) none of the mentionedI got this question by my school principal while I was bunking the class.I would like to ask this question from CFG-Eliminating Useless Symbols topic in section Properties of Context Free Languages of Automata Theory

Suppose A->xBz and B->y, then the simplified grammar would be:(a) A->x

1.	Suppose A->xBz and B->y, then the simplified grammar would be:(a) A->xyz(b) A->xBz\|xyz(c) A->xBz\|B\|y(d) none of the mentionedI got this question by my school principal while I was bunking the class.I would like to ask this question from CFG-Eliminating Useless Symbols topic in section Properties of Context Free Languages of Automata Theory
Answer» The correct choice is (a) A->XYZ For explanation: For the first step, substitute B in first production as it only produces terminal and remove B production as it has already been utilized. We GET A->xBz\|xyz and now, as B has no production, we eliminate the TERMS which HOLD the variable B, thus the answer remain A->xyz.

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