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Suppose det ⎡⎢⎢⎢⎢⎣n∑k=0kn∑k=0nCk k2n∑k=0nCk kn∑k=0nCk 3k⎤⎥⎥⎥⎥⎦=0 hold for some positive integer n. Then n∑k=0nCkk+1 equals

Answer» Suppose det


nk=0knk=0nCk k2nk=0nCk knk=0nCk 3k


=0

hold for some positive integer n. Then nk=0nCkk+1 equals


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