1.

Suppose f(x)=x3+ax2+bx+c satisfies f(–2)=−10 and takes the extreme value 5027 at x=23. Then the value of a+b+c is

Answer» Suppose f(x)=x3+ax2+bx+c satisfies f(2)=10 and takes the extreme value 5027 at x=23. Then the value of a+b+c is


Discussion

No Comment Found