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Suppose mean of a series of 5 items is 30. Four values are, 10,15,30 and 35 respectively. Find the missing (5th) value of the series. |
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Answer» Solution :Assume 5th value as `X_(5)`. `barX=(X_(1)+X_(2)+X_(3)+X_(4)+X_(5))/N` `"GIVEN: "X_(1)=10,X_(2)=15,X_(3)=30,X_(4)=35,X_(5)=?` `barX=30,N=5` `30=(10+15+30+35+X_(5))/5=(90+X_(5))/5` `:.""30xx5=90+X_(5)` `Or,150=90+X_(5)` `:.""X_(5)=150-90` `=60` THUS, Value of the5th item = 60. |
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