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Suppose p(x)=a0+a1x+⋯+anxn. If |p(x)|≤|ex−1−1| for all x≥0, then the maximum value of |a1+2a2+⋯+nan| is equal to

Answer» Suppose p(x)=a0+a1x++anxn. If |p(x)||ex11| for all x0, then the maximum value of |a1+2a2++nan| is equal to


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