Suppose refractive index mu is given as mu= A + (B)/(gamma^(2))where A and B are constants and gamma is wavelength, then dimensions of B are same as that of

Suppose refractive index mu is given as mu= A + (B)/(gamma^(2))where A

1.	Suppose refractive index mu is given as mu= A + (B)/(gamma^(2))where A and B are constants and gamma is wavelength, then dimensions of B are same as that of
Answer» wavelength volume pressure area Solution :As `mu= ("VELOCITY of light in vacuum ")/("velocity of light in MEDIUM")` hence `mu` is dimensionless, THUS each term on the RHS of given equation should be dimensionless. `:. (B)/(lambda^(2))` is dimensionless, i.e, B should have dimensions of `lambda^(2)` i.e, `L^(2)` area.