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Suppose that the electric field amplitude of an electromagnetic wave us `E_0=120 N// C` and that its frequency is `50.0 MHz`. (a) Determine` B_0,omega,k` and `lambda`, (b) find expressions for `E` and `B`. |
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Answer» (`a`) `i` Using `C=(E_(0))/(B_(0))` we get `B_(0)=(E_(0))/(C )=(120)/(3xx10^(8))=4xx10^(-7)T=400nT` (`ii`) `omega=2piv=2xxpixx50xx10^(6)=3.14xx10^(8)rad//Sec` (`iii`) `c=ulambdaimplieslambda=(C )/(u)=(3xx10^(8))/(50xx10^(6))=6m` (`iv`) `K=(2pi)/(lambda)=(2pi)/(6)=(2xx3.14)/(6)=1.05m^(-1)` (`b`) `vecE=E_(0)sin(kx-omegat)` `=120sin(1.05x-3.14xx10^(8)t)` `B=B_(0)sin(kx-omegat)` `=400xx10^(-9)sin(1.05x-3.14xx10^(8)t)` |
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