1.

Suppose that the rotation of the earth was increased such that the centripetal acceleration was equal to the gravitational acceleration at the equator (i) Find the speed of a person standing at the equator and (ii) How long would a day be ?

Answer»


Solution :`v^(2)//r =G, v= sqrt(rg) = sqrt(6400 xx 10^(3) xx 9.8) = 7.9 km//s, T = 2pir//v = 2PI xx 6400 xx 10^(3)//7.9 xx 10^(3) = 5070 s`


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