Suppose that the uncertainty in determining the position of an electron in an orbit is 0.6A what is the uncertainty in its momentum?

Suppose that the uncertainty in determining the position of an electro

1.	Suppose that the uncertainty in determining the position of an electron in an orbit is 0.6A what is the uncertainty in its momentum?
Answer» <P> Solution :`/_\x=`uncertainty in position of an electron`=0.6A=0.6xx10^(-10)m` `/_\p`=uncertainty in momentum=? Heisenberg.s uncertainty principle states that, `/_\p=h/(4pi./_\x)` h=planck.s constant`=6.626xx10^(-34)kg m^(2)s^(-1)` `:./_\p=(6.626xx10^(34)kgcancel(m^(2)s^(-1)))/(4xx3.14xx0.6xx10^(-10)CANCEL(m))` `=(6.626xx10^(-34)xx10^(10))/(7.536)` uncertainty in momentum`=0.8792xx10^(-24)kgms^(-1)(or)` `=8.792xx10^(-25)kgms^(-1)`