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Suppose the emf of the battery, the circuit shown varies with time `t` so the current is given by `i(t)=3+5t`, where `i` is in amperes & `t` is in seconds. Take `R=4Omega, L=6H` & find an expression for the battery emf as function of time. |
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Answer» Correct Answer - `42+20t volt` `E=iR+L(di)/(dt)=(3+5t)4+6xx5=42+20t` |
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