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Suppose the energy liberated in the recombination of a hole-electron pair is converted into electromagnatic radiation. If the maximum wavelength emitted is 660nm, what is the band width? (Use `h=6.6xx10^(-34) J-s)`A. 0.1875 eVB. 1.875 eVC. 0.938 eVD. 0.625 eV |
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Answer» Correct Answer - B Here `lambda=660 nm=660xx10^(-9)m` Band gap `E_(g)=(hc)/(lambda)=((6.6xx10^(-34))xx(3xx10^(8)))/(660xx10^(-9))` `(6.6xx10^(-34)xx3xx10^(8))/(660xx10^(-9)xx1.6xx10^(-19))ev` `=1.875 eV` |
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