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Suppose the frequency of the source in the above example can be varied (a) What is the frequency of the source at which resonance occurs ? (b) Calculate the impedeance, the current and power dissipated at the resonant condition. |
Answer» (a) The frequency at which the resonance occurs is `omega_(0)=(1)/sqrt(LC)=(1)/(sqrt(25.48xx10^(-3)xx796xx10^(-6)))` =222.1rad/s `v_(r)=(omega_(0))/(2pi)=(221.1)/(2xx3.14)Hz=35.4Hz` (b) The impedance Z at resonant condition is equal to the resistance: Z=R=`3Omega` The rms current at resonance is `=(V)/(Z)=(V)/(R)=((283)/(sqrt(2)))(1)/(3)=66.7A` The power dissipated at resonance is `P=I^(2)xxR=(66.7)^(2)xx3=13.35kW` You can see that in the present case, power dissipated at resonance is more than the power dissipated in Example 7.8. |
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