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Suppose unknowingly you wrote the universal gravitational constant value as G = 6.67 xx 10^(11) Instead of the correct value G = 6.67 xx 10^(-11), what is the acceleration due to this new acceleration due to gravity, what will be your weight W'? |
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Answer» Solution :DATA: IncorrectGravitationalconstant ` G = 6.67 xx10^(11) "Nm"^(2) kg^(-2)` Massof the Earth `M_(e) = 5.972 xx10^(24) ` kg Radiusof the Earth `R_(e) = 6371"km (or) " 6371 xx10^(3)` m Acceleration due to gravityg. ` = (GM_(e))/(R_(e)^(2))` ` g. = (6.67 xx10^(11)xx5.97 xx10^(24))/((6371 xx10^(3))^(2))` ` = (39.8332 xx10^(35))/(4.0589641 xx10^(13)) = 9.81 xx10^(22)` `g . = 10^(22) g ` New weight `W. = Mg. = M (10^(22)g) = 10^(22) mg ` |
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