Suppose unknowingly you wrote the universal gravitational constant value as G = 6.67 xx 10^(11) Instead of the correct value G = 6.67 xx 10^(-11), what is the acceleration due to this new acceleration due to gravity, what will be your weight W'?

Suppose unknowingly you wrote the universal gravitational constant val

1.	Suppose unknowingly you wrote the universal gravitational constant value as G = 6.67 xx 10^(11) Instead of the correct value G = 6.67 xx 10^(-11), what is the acceleration due to this new acceleration due to gravity, what will be your weight W'?
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/data-25577" style="font-weight:bold;" target="_blank" title="Click to know more about DATA">DATA</a>: IncorrectGravitationalconstant ` <a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a> = 6.67 xx10^(11) "Nm"^(2) kg^(-2)`<br/> Massof the Earth `M_(e) = 5.972 xx10^(24) ` kg<br/> Radiusof the Earth `R_(e) = 6371"km (or) " 6371 xx10^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` m<br/>Acceleration due to gravityg. ` = (GM_(e))/(R_(e)^(2))`<br/> ` g. = (6.67 xx10^(11)xx5.97 xx10^(24))/((6371 xx10^(3))^(2))`<br/>` = (39.8332 xx10^(35))/(4.0589641 xx10^(13)) = 9.81 xx10^(<a href="https://interviewquestions.tuteehub.com/tag/22-294057" style="font-weight:bold;" target="_blank" title="Click to know more about 22">22</a>)`<br/>`g . = <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(22) g `<br/> New weight `W. = Mg. = M (10^(22)g) = 10^(22) mg `</body></html>